NOTE:- i^(2n) = (i^2)^n = (-1)^n ; where n = natural number
Thus i^2 = -1 & i^3 = -1*i = -i
Hence 2i^2 + 3i^3 = (2*-1) + (3*-i) = -2 - 3i
2i^2 + 3i^3
i raised to the 2 power is -1.
2 (-1) +3i^3
Multiply 2 by -1 to get -2.
-2 +3i^3
i raised to the 3 power is -i.
-2 + 3(-i)
Multiply 3 by -i to get -3i.
-2-3i
2i^2+3i^3 simplified is equivalent to -2-3i
Further Reading