Express 48 and 60 as a product of their prime factors

Asked on by hadjartahax

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justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

48 and 60 have to be expressed as a product of their prime factors.

Write each of the numbers as a product of a prime and another number starting with the smallest prime number 2 and moving to larger prime numbers.

48 = 2*24

= 2*3*8

= 2*3*2^3

= 2^4*3

60 = 2*30

= 2*3*10

= 2*3*2*5

= 2^2*3*5

The prime factorization of 48 is 2^4*3 and for 60 it is 2^2*3*5

durbanville's profile pic

durbanville | High School Teacher | (Level 2) Educator Emeritus

Posted on

48 as a product of its prime factors is 2^4. 3 (or

60 as a product of its prime factors is 2^2.3.5  (or

Remember prime factors are those numbers that can only be divided by themselves and 1; for example, 3 can only be divided by 3 and by 1. You won't find 3 as an answer in any other times table.

So do a mini division sum whenever you have to find prime factors and start with the smallest number that goes into the number you are looking for prime factors  for example try 2 and if that won't work (because it's an odd number ), try 3. If 3 won't work try 5 or 7 or 11 ,13,17,19,23,and so on remembering not to use a number that appears in any other times table except its own!

Good luck.

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