Student Comments

aruv | Student

`log_9 2`

`` Let

`x=log_9 2`

`2=9^x`

`ln(2)=ln(9^x)`

`ln(2)=xln(9)`

`x=(ln(2))/(ln(9))`

`=.31546`

`=.3155`

Therefore

`log_9 (2)=.3155`

Student Comments

aruv | Student

`log_9 2`

`` Let

`x=log_9 2`

`2=9^x`

`ln(2)=ln(9^x)`

`ln(2)=xln(9)`

`x=(ln(2))/(ln(9))`

`=.31546`

`=.3155`

Therefore

`log_9 (2)=.3155`