Evaluate the limit of the function (x^2-3x+2)/(x^2-4) using L'Hospital rule.
As you have not specified what x is tending to, I take it as 2.
We have to find the value of lim x--> 2 [(x^2-3x+2)/(x^2-4)]
If we substitute x = 2, we get the indeterminate form 0/0. So we use L'Hopital's Rule and substitute the numerator and the denominator by their derivatives
=> lim x-->2 [(2x -3)/(2x)]
substitute x = 2
=> (4 - 3) / 4
The required value of lim x--> 2 [(x^2-3x+2)/(x^2-4)] = (1/4)
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