Evaluate the limit of expression 4cosx-6sin^2x+3tan^2x. x-->x0 , x0=60 degrees

Expert Answers

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We have to find the value of lim x--> 60 degrees[ 4cos x - 6(sin x)^2 + 3*tan x)^2]

Here we see that cos 60 , (sin 60)^2 and (tan 60)^2 are defined, so we can just substitute x with 60.

Substituting x = 60 degrees

4cos x - 6(sin x)^2 + 3*tan x)^2

=> 2 - 6*(3/4) + 3* 3

=> 2 - 4.5 + 9

=> 6.5

The required value of lim x--> 60 degrees[ 4cosx - 6sin^2x + 3tan^2x] is 6.5

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