# Evaluate Integral [upper limit 4, lower limit 1] of 1/sqrt(x) dx

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### 1 Answer

`y = int_1^4 1/sqrt(x)dx`

`y = int_1^4 x^(-1/2)dx`

`y = intx^(-1/2)dx = x^(1/2)/(1/2) = 2sqrt(x)`

Therefore,

`y = int_1^4 1/sqrt(x)dx = 2(sqrt(4)-sqrt(1)) = 12(2-1) = 2`

`y = int_1^4 1/sqrt(x)dx = 2`