Evaluate the integral [ln(x)/(x) dx]

Evaluate `int (lnx)/x dx` : We ` `` `let `u=lnx` . Then `du=1/xdx` and we have: `intudu=1/2u^2+C` . Substituting for `u` we get `1/2(lnx)^2+C` . Thus the integral evaluates as `1/2(ln(x))^2+C`

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Evaluate the integral [ln(x)/(x) dx]

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embizze | High School Teacher | (Level 2) Educator Emeritus

Posted on May 2, 2012 at 2:56 AM

Evaluate `int (lnx)/x dx` :

We ` `` `let `u=lnx` . Then `du=1/xdx` and we have:

`intudu=1/2u^2+C` . Substituting for `u` we get `1/2(lnx)^2+C` .

Thus the integral evaluates as `1/2(ln(x))^2+C`

Sources:

https://en.wikipedia.org/wiki/Logarithm

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Evaluate the integral [ln(x)/(x) dx]

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