Evaluate the integral integrate of (e^(3x))/((e^x+1))dx

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To evaluate the integral, we have a substitution.

`int{e^(3x)}/{e^x+1}dx`

`=int{(e^x)^3}/{e^x+1}dx`   let `u=e^x` , so `du=e^xdx`

`=int u^2/{u+1}du`   now let `v=u+1` so `dv=du`

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