evaluate the integral (dt)/(3-4t) the lower limit is 5 and upper is 2
move from 1st to second by multiplying denominator by (-1).
From 2nd to 3rd swap lower and upper bound by multiplying the integral by (-)
next step we know that int(1/x)=lnx. Since our problem has 4t-3, we have to make up for it by dividing by 4.
Hope this clarify the work.
` ` `int_2^5dt/(4t-3)=`
`1/4*ln(4t-3) between 2 and 5=`