# Evaluate the integral. (Complete the square if necessary) `int (x-1)/(sqrt(x^2 - 2x)) dx`

*print*Print*list*Cite

### 2 Answers

To solve this integral make a secant substitution:

`x-1 = sec theta` so that `dx = sec theta tan theta d theta`

Rewrite the integral then as

`I = int (sec theta)/sqrt(sec^2 theta - 1) sec theta tan theta d theta` = `int (sec^2 theta tan theta)/sqrt(sec^2 theta - 1) d theta ` `= int sec^2 theta d theta`

since `x^2 - 2x = (x-1)^2 - 1` (completing the square in the denominator of the integrand as suggested), and since `sqrt(sec^2 theta - 1) = tan theta`

Now,

`int sec^2 theta d theta = tan theta + c` where `c` is a constant of integration, giving

`I = tan theta + c`

``Putting `x - 1 = sec theta` back into this, note that `(x-1)^2 -1 = sec^2 theta - 1 ` `= tan theta` , so that `tan theta = sqrt((x-1)^2 - 1) = sqrt(x^2 - 2x)`

**This gives then that**

**`I = sqrt(x^2 - 2x) + c` where `c` is a constant of integration**

NB see Example 6 and solution in the reference link below

**Sources:**

the solution is sqrt(x^2-2x)