`y = int(ln(x)+2)^2/xdx`
Let `u = ln(x)` , then,
`du = 1/x dx`
Then the integral changes into,
`y = int(u+2)^2du`
`y = (u+2)^3/3 +c `
Where c is an arbitrary constant.
`y = (ln(x)+2)^3/3 + c`
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