# Evaluate the function at the indicated value of x FunctionValue f(x) = `log_8(x)` x = 2 f(2)=______Can someone help me solve this?

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### 1 Answer

`f(x)= log_8 x `

`==gt x= 2`

We need to find f(2).

Then, we will plug in 2 into the function.

`==gt f(2)= log_8 2 `

Now we will use the change base property to simplify.

`==gt f(2)= log_8 2 = (log_2 2)/(log_2 8) = 1/3 `

`==gt f(2)= 1/3`