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We have the fraction 2i/(1 + i)

Making the denominator a real number

2i/(1 + i)

=> 2i( 1 - i)/(1 + i)(1 - i)

=> (2i - 2i^2) / 1 - i^2

=> (2i + 2)/ ( 1 + 1)

=> 1 + i

Therefore we get (1 + i)

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