Evaluate (definite integral) abs(2x-5)/(x+1)dx from 0 to 6

Expert Answers info

sciencesolve eNotes educator | Certified Educator

calendarEducator since 2011

write5,349 answers

starTop subjects are Math, Science, and Business

You need to evaluate the definite integral such that:

`int_0^6 |2x-5|/(x+1)dx`

You need to use the absolute value property such that:

`|2x-5| = {(2x-5, 2x-5gt=0),(5-2x,2x-5lt0):}`

Since the function `y=2x-5`  is negative if `x in [0, 2.5]`  and it is positive if `x in [2.5,6], ` you need to split the integral such that:

`int_0^6 |2x-5|/(x+1)dx = int_0^2.5 (5-2x)/(x+1)dx + int_2.5^6...

(The entire section contains 195 words.)

Unlock This Answer Now

check Approved by eNotes Editorial