EVALUATE THE DEFINITE INTEGRAL 2 ∫dx/(x^2(√4x^2 + 9)) 1 INTEGRATION, SINGLE VARIABLE CALCULUS,TRIGONOMETRIC SUBSTITUTION
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You should factor out 9 under the square root such that:
`int_1^2 (dx)/(x^2sqrt((4/9)x^2+1))`
You should come up with the substitution `x = (3/2)(cot x) =gt x^2 = (9/4)cot^2 x.`
Differentiating`x = (3/2)(cot x)` with respect to x yields:
`dx = -(3/2)(1/(sin^2 x))`
`int_1^2 (dx)/(x^2sqrt((4/9)x^2+1)) = int_1^2 (-(3/2)(1/sin^2 x)dx)/(((9/4)cot^2 x)sqrt(cot^2 x+1))`
You ned to substitute `1/(sin^2 x)` for `(cot^2 x+1)` such that:
`int_1^2 (-(3/2)(1/sin^2 x)dx)/(((9/4)cot^2 x)sqrt(cot^2 x+1)) =int_1^2 (-(3/2)(1/sin^2 x))/(((9/4)cot^2 x)sqrt(1/(sin^2 x)))`
`int_1^2 (-(1/sin^2 x))/(((3/2)cot^2 x)(1/(sin x)))`
`int_1^2 (-(1/sin x)dx)/((3/2)cot^2 x)`
You need to remember that `cot x = cos x/sin x`
`int_1^2 (-(1/sin x))/((3/2)(cos^2 x)/(sin^2 x))`
`int_1^2 (-dx)/((3/2)(cos^2 x)/(sin x))`
`(2/3)int_1^2...
(The entire section contains 2 answers and 409 words.)
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