evaluate the definite integral [0,1] of ln(4+x^2)dx
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You should use integration by parts such that:
`int udv = uv - int vdu`
Considering `u=ln(4+x^2)` and `dv = dx` yields:
`u=ln(4+x^2) => du = (2x)/(4+x^2)`
`dv = dx => v= x`
Using the formula of integration by parts yields:
`int ln(4+x^2) dx = xln(4+x^2)- int (2x^2)/(4+x^2)dx`
`int ln(4+x^2) dx = xln(4+x^2)- 2int (x^2)/(4+x^2)dx`
You need to evaluate `int (x^2)/(4+x^2)dx` , hence, you...
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