Equations . Solve for x and y if y=6/x and 2^(x+y)=32 .

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We have to solve for x and y given that y=6/x and 2^(x+y)=32

2^(x+y)=32

=> 2^(x + y) = 2^5

=> x + y = 5

substitute y = 6/x

x + 6/x = 5

=> x^2 - 5x + 6 = 0

=> x^2 - 3x - 2x +...

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We have to solve for x and y given that y=6/x and 2^(x+y)=32

2^(x+y)=32

=> 2^(x + y) = 2^5

=> x + y = 5

substitute y = 6/x

x + 6/x = 5

=> x^2 - 5x + 6 = 0

=> x^2 - 3x - 2x + 6 = 0

=> x(x - 3) - 2(x - 3) = 0

=>(x - 2)(x - 3) = 0

=> x = 2 and x = 3

y = 3 and y = 2

The solution for x and y are (2,3 ) and (3, 2)

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