We need to find x if 7^(3x-5) = 7^-2
7^(3x-5) = 7^-2
as the exponent 7 is common we can equate the exponent
=> 3x - 5 = -2
=> 3x = 5 - 2
=> 3x = 3
=> x = 3/3
=> x = 1
The solution is x = 1.
We need to find x if 7^(3x-5) = 7^-2
7^(3x-5) = 7^-2
as the exponent 7 is common we can equate the exponent
=> 3x - 5 = -2
=> 3x = 5 - 2
=> 3x = 3
=> x = 3/3
=> x = 1
The solution is x = 1.