Emily rows six miles downstream in 1 hour and her friend Ashley, rowing 1 mile per hour faster, completes the return trip in 2 hours. If Emily and Ash ley were rowing separately, who would...
Emily rows six miles downstream in 1 hour and her friend Ashley, rowing 1 mile per hour faster, completes the return trip in 2 hours.
If Emily and Ash ley were rowing separately, who would complete their trip first and by how long? Round to the nearest hundredth, if necessary.
speed of the current:2mph.
rowing speed of Emily.
rowing speed of Ashley.
Emily rows downstream (with the current); she takes 1 hour to go 6 miles. The current is 2mph and Emily's total speed is 6mph (she covers 6 miles in 1 hour so 6mph) so Emily rows at 4mph.
Ashley rows 1 mph faster s0 Ashley's rowing speed is 5mph.
(Check -- rowing at 5mph against a current of 2mph means she travels at 3mph. Going 6 miles at 3mph requires 2 hours, which is the time given.)
Suppose that Emily and Ashley separately rowed the entire 12 mile trip -- 6 miles downstream and 6 miles back upstream.
Emily rows at 4mph. Thus her downstream speed is 6mph (with the current) and her upstream speed is 2mph (against the current). Use `d=rt ==> t=d/r` so the time required is the distance divided by the rate. So Emily's time for the course is the sum of the downstream and upstream legs. `t=6/6+6/2=1+3=4` so Emily's course time is 4 hours.
Ashley rows at 5mph. ` `Her downstream speed is 7mph and her upstream speed is 3mph. The time is
`t=6/7+6/3=2 6/7~~2.86` hours.
Ashley's course time is 2.86 hours.
Ashley will complete her trip first by approximately 1.14 hours. (1 hour and 8.4 minutes)