To solve, apply the formula of power.

`P=IV`

Plug-in the given power consumption and the voltage rating of L1.

`0.5=I*6`

Then, divide both sides by 6 to get the value of I.

`0.5/6=(I*6)/6`

`0.083=I`

**Hence, the current passing through L1 is 0.083A.**

To solve, apply the formula of power.

`P=IV`

Plug-in the given power consumption and the voltage rating of L1.

`0.5=I*6`

Then, divide both sides by 6 to get the value of I.

`0.5/6=(I*6)/6`

`0.083=I`

**Hence, the current passing through L1 is 0.083A.**