# electricityThere are three 100 ohm resistors. Draw the arrangement of resistors such that the total resistance of the combination is: 100 ohm, 200 ohm, 300 ohm, 50 ohm, 33.3 ohm, 150 ohm, 66.7 ohm

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It is an interesting problem and would be ** better if put in Q&A section **as there is only one possible solution as under:

100 ohm -> using single resistor, not putting other two in circuit

200 ohm -> using 2 resitors in series, not putting the third in circuit

300 ohm -> using all 3 in series

50 ohm -> using 2 resistors in parallel, not putting the third in circuit

150 ohm -> using one resistor put in series with the other two put in parallel

66.7 ohm -> using one resistor put in parallel with the other two put in series

It uses the basic principle of addition of resistances in series and parallel.

Asuming R1, R2, R3, ---- are the given resistances of the resistors and R is the resultant resistance of the combination then:

In a series circuit, R = R1 + R2 + R3 + ----

In a parallel circuit 1/R = 1/R1 + 1/R2 + 1/R3 + ----

In a combination circuit, where both parallel and series circuits are used, we calculate the combined resistance of the sub-circuits (series or parallel) using the above addition rules till the whole circuit is resolved to a single type (series or parallel.