# Ecuation and x,y intercepts5x-15y=120

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### 3 Answers

To find the x and y intercepts simply substitute y = 0 and x = 0 resp. Then calculate the value of the variable that is left.

Let's find the y intercept, x = 0

5x - 15y = 120

=> -15y = 120

=> y = 120/-15

=> y = -8

To find the x intercept, y = 0

5x - 15y = 120

=> 5x = 120

=> x = 120/5

=> x = 24

Therefore the x-intercept is (24 , 0) and the y-intercept is (0, -8).

The y intercept is the value of y when x = 0.

When x = 0, the equation looks like this

-15y = 120

Divide both sides by -15 and you get

y = -8 -- that's the y intercept.

The x intercept is the value of x when y = 0

5x = 120

x = 24

To find x intercept, we'll put y = 0 and we'll solve for x:

f(x) = y = 0

We'll divide by 5:

5x-15y=120

x - 3y = 24

We'll isolate 3y to the left side:

-3y = -x + 24

We'll divide by -3:

y = x/3 - 8

For y = 0 => x/3 - 8 = 0

x - 24 = 0

x = 24

The line 5x-15y=120 is intercepting x axis in the point (24 ; 0).

We'll determine y intercept and we'll put x = 0

5*0 - 15y=120

-15y=120

y = -120/15

y = -8

The line 5x-15y=120 is intercepting y axis in the point (0 ; -8).