# Earth (m= 5.98 x 10 to the 24 power kg) moving with an orbital speed equal to 29700 m/s. Answer in units of kg x m/s.Calculate the magnitude of the linear momentum for each of the following cases...

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Linear momentum of the earth = earths mass in Kg* earths lenear velocity in m/s at the momemt

=(5.98*10^24 kg)(29700m/s)

=1.77606*10^29 kg m/s

Given:

Mass = m = 5.98*(10^24) kg, and

Speed = v = 29700 m/s

We know:

Momentum = m*v = [5.98*(10^24)]*29700 = 1.77606*(10^29) kg x m/s

Answer: Magnitude of linear momentum of earth is 1.77606*(10^29) kg x m/s