Each corner of a right angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of this arrangement. "A" exerts force F on "B". An equal force F is exerted by "C" on "B" (`/_` ABC= 90 degrees). Determine an expression for the net force on "B".

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Because the charges are identical, they repel each other. Therefore the direction of the force that `A` exerts on `B` is directed from `A` to `B` (outside the triangle `ABC` ). The direction of the force that `C` exerts on `B` is from `C` to `B` (also outside the triangle...

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Because the charges are identical, they repel each other. Therefore the direction of the force that `A` exerts on `B` is directed from `A` to `B` (outside the triangle `ABC` ). The direction of the force that `C` exerts on `B` is from `C` to `B` (also outside the triangle `ABC` ).

The net force is the vector sum of these two forces. Both forces have equal magnitude `F` and the angle between them is `90` degrees, and the magnitude of the net force is the length of the hypotenuse of a right triangle with the legs of length `F.` It is `F*sqrt(2)` (this is the answer for "an expression").

The direction of the net force is `45` degrees to both forces outside of the triangle `ABC,` because the parallelogram of forces is a square in this case. Please look at the picture attached.

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