You need to evaluate the speed of the body along x axis, such that:
`v_x = v*cos theta`
`theta = tan^(-1)(v_y/v_x) =gt theta = tan^(-1)(1.49) ~~56.13^o`
You need to evaluate the magnitude, such that:
`v = sqrt(v_x^2+v_y^2)=gt v = sqrt(2.45^2+3.67^2)`
`v = sqrt(6+13.46) =gt v ~~ 4.41`
Hence, evaluating the magnitude of velocity vector `bar v = 2.45bar x + 3.67bar y` , yields `v ~~ 4.41` and evaluating the speed of the body along x axis, yields `v_x=2.45` .