You have provided the equation e^(3x) = 12, and we have to solve this for x.

We first take the log to the base e for both the sides.

=> ln e^(3x) = ln 12

use the exponent rule for algorithm which states that log a^b = b*log a.

=> 3x ln e = ln 12

ln e = 1

=> 3x = ln 12

=> x = (ln 12)/3

=> x = 2.484 / 3

=> x = .8283

**Therefore x is equal to (ln 12)/ 3 or 0.8283. **

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