First these terms, momentum, impulse and force, they all are vectors that means they are quantities with a direction. So when you specify their value you have to mention the direction also.

1) Momentum = Mass x Velocity

In average terms,

Average momentum = Mass x Average velocity

The avergae velocity of the man = 2000 m/ (12*60) sec towards the direction from house to shop

= 2.778 ms-1

Average momentum = 80 kg x 2.778 ms-1 towards the same direction above.

= 222.24 kgms-1

2)

In this problem we have to make some assumptiosn, otherwise the answer is not complete,

We have to assume that tennis ball is stationary when it was hit by the racket. (as in serve of a tennis match)

Force = Rate of momentum change

Rate of momentum change = (Final momentum - Initial momentum)/ time

Lets take direction of ball after it hit the racket as positive.

Rate of moentum change

= (0.075 x 30 - 0.075 x 0) / 0.0002 kgms-2

= 11250 N

= 11.25 kN in the direction of ball movement

c) Impulse = Force x Time = F x dt

or in other words, I = momentum change

I = F x dt = m x a x dt

a x dt is velocity change dv

Therefore I = m x dv

I = 6 kg x (12 -0) ms-1

I = 72 Ns-1 in west direction (Newtons persecond)

d)

Let's take the downward direction as positive. Then the velocity downward is positive while the velocity upwards is negative

Then the momentum change = Final momentum - Intital momentum

= 1.2 x (-0.6) kgms-1 - 1.2x2 kgms-1

= -0.72 - 2.4 kgms-1

= -3.12 kgms-1

The moemntum change is -3.12 kgms-1 downwards or +3.12 kgms-1 upwards.

e)

You have done a typing mistake here. Therefore I am assuming that 1.9 x 105 is actually 1.9 x 10^5 N (ten to the power 5, otherwoise this doesnt make any sense) and 7.84 x 104 as 7.84 x 10^4 respectively.

First we can find the acceleration of the rocket due to the force using F = ma,

1.9 x 10^5 N = 7.84 x 10^4 kg x a

a = 2.423 ms-2

Assuming the rocket was initially stationary (ie V1 = 0)

V = V1 + a*t

V = 0 + 2.423 ms-2 x 9 s

= 21.807 ms-1

The final velocity is 21.807 ms-1