# dy/dx = 14x^2 + 3x, what is y in terms of x.

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### 1 Answer

The derivative of y with respect to x, `dy/dx = 14x^2 + 3x`

`dy/dx = 14x^2 + 3x`

=> `dy = (14x^2 + 3x) dx`

take the integral of both the sides

=> `int dy = int (14x^2 + 3x) dx`

=> `y = 14*x^3/3 + 3x^2/2 + C`

Here, C is a constant; this is included as the derivative of a constant is always 0.

**The expression for `y = 14*x^3/3 + 3x^2/2 + C` **