# A DVD rotates from rest to an angular speed of 31.4 rad/s in a time of 0.892 seconds. A) What is the angular acceleration of the disc (assuming uniform acceleration").  B) Through what angle does...

A DVD rotates from rest to an angular speed of 31.4 rad/s in a time of 0.892 seconds.

A) What is the angular acceleration of the disc (assuming uniform acceleration").  B) Through what angle does the disc turn while coming up to speed? C) How many revolutions does it go through?  D) If the disc is 9.9 cm across at its widest point, find the tangential speed of a microbe riding on the rim of the disc when t=0.892s.  E) What is the magnitude of the tangential acerleration of the microbe at the given time?

valentin68 | Certified Educator

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The uniform angular acceleration is (like the linear acceleration)

`epsilon = (Delta(omega))/(Delta(t)) =31.4/0.892 =35.2 (rad)/s^2`

The angle traveled in time `t` is (like the linear space)

`alpha = epsilon*t^2/2...

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