`(dr)/(ds) = e^(r-2s) , r(0)=0` Find the particular solution that satisfies the given initial condition.

Expert Answers

An illustration of the letter 'A' in a speech bubbles

This differential equation can be solved by separating the variables.

`(dr)/(ds) = e^(r - 2s)`

Dividing by e^r and multiplying by ds results in the variables r and s on the different sides of the equation:

`(dr)/e^r = e^(-2s)ds`

This is equivalent to

`e^(-r) dr = e^(-2s)ds`

Now we can take the integral of the both sides of the equation:

`-e^(-r) = 1/(-2)e^(-2s) + C` , where C is an arbitrary constant.

From here, `e^(-r) = 1/2e^(-2s) - C`

and `-r = ln(1/2e^(-2s) - C)`

or `r = -ln(1/2e^(-2s) - C)`

Since the initial condition is r(0) = 0, we can find the constant C:

`r(0) = -ln(1/2e^(-2*0) - C) = -ln(1/2 - C) = 0`

This means `1/2 - C = 1`

and `C = -1/2`

Plugging C in in the equation for r(s) above, we can get the particular solution:

`r = -ln((e^(-2s) + 1)/2)` . This is algebraically equivalent to

`r = ln(2/(e^(-2s) + 1))` . This is the answer.

Approved by eNotes Editorial Team

Posted on

Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial