Don, Ric and Mike were in a committee to build a float for the homecoming parade. Each of them thoughtthat he could build it (continued...)
alone in 16 hours. Don started work at 8:00 a.m., Ric at 8:30 a.m. and Mike at 9:00a.m. What time did they finish the float? (use one variable)
Use the format “Given, Required, Solution, Checking, Final Answer”
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Time needed for each to build alone = 16 hrs.
Don works at 8
Ric workds at 8:30
Mike works at 9:00
Time they finished the boat (T).
If T is the time they all finish the boat, then, the total hours of work for the workers are:
Don works (T -8) hours.
Ric works (T-8.5) hours.
Mike workds (T-9) hours.
The works done for each in an hour = `1/16` of the boat.
==> Now we will find the work done at T hour for each.
Don = `(T-8)*1/16 `
`` Ric = (`T-8.5)*1/16 `
`` Mike = `(T-9) * 1/16`
`` Then the total will be the finished boat = 1.
==> `(T-8)/16 + (T-8.5) /16 + (T-9)/16 = ` 1
==> T-8 + T- 8.5 + T-9 = 16
==> 3T -25.5 = 16
==> 3T = 41.4
==> T = `41.4/3` = 13.8
Now we will convert to Time.
13 = 1 pm
0.8 = 0.8*60= 48 min.
Then , the time they finished the boat is 13:48 OR 1:48.
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