A dominant gene (H) produced wire-haired texture in dogs; its recessive allele (h) produces smooth hair. A heterozygous female dog is mated with a smooth-haired male dog. What phenotypes are...

A dominant gene (H) produced wire-haired texture in dogs; its recessive allele (h) produces smooth hair. A heterozygous female dog is mated with a smooth-haired male dog. What phenotypes are expected in a large number of puppies and in what ratios?

Expert Answers
jerichorayel eNotes educator| Certified Educator

To solve this problem, let us use the punnett square in order to determine the phenotype rations of the offspring of a heterozygous female dog (Hh) and a recessive male dog (hh). 

The heterozygous female contains a dominant and recessive trait (genotype: Hh) while the smooth-haired male contains only recessive trait (genotype: hh). Doing the punnett square we can have:

      h      h

H    Hh    Hh

h    hh    hh

Results:

2Hh or 50% of the puppies will have a wire-haired texture.

2hh or 50% of the puppies will have a smooth-haired texture.

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