Domain of functionh(x)=( 5-x)/square root 5x-125

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sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

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Notice that the function does not hold for values of x that cancel hence, you need to eliminate the zeroes of such that:

Notice that the domain does not contain the value .

There exists a second condition to be considered for the square root to exist:

Hence, evaluating the domain of the function yields

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

The denominator of the function impose the domain of definition.

We'll impose the constraint of existence of the function:

5x-125 > 0

We've imposed that the expression to be strictly positive, since the sqrt 5x-125 represents the denominator. According to the rule, the values of denominator have to be other than zero.

We'll divide by 5:

x - 25>0

We'll add 25 both sides:

x > 25

The domain of definition is the interval of x values, that are strictly greater than 25!

x belongs to (25, +infinite)

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