This is related to derivatives.
`y = x^5 ----(1)`
Let us say for for marginal change in `deltax` the change in y is `deltay `
`y+deltay = (x+deltax)^5 ----(2)`
`deltay = (x+deltax)^5-x^5`
Rate of change means `(deltay)/(deltax)`
`(deltay)/(deltax) = [(x+deltax)^5-x^5]/(deltax)`
When `(deltay)/(deltax)` be a small marginal change;
`lim_(xrarr0)(deltay)/(deltax) ` referred as the derivative of a function.
Therefore rate of marginal change can be expressed as the derivative.
Rate of change at x = 2 and y = 32;
`((dy)/dx)_(x=2) = 5*2^4 = 80`
So the statement is correct and we should agree with that.