# I know how to get the answer to this question, but I want to know if there's an algebraic way to solve it, with proportions. (I always have trouble with proportions.) Please use math symbols so I...

I know how to get the answer to this question, but I want to know if there's an algebraic way to solve it, with proportions. (I always have trouble with proportions.)

Please use math symbols so I can understand how to do this easily, too.

Thank you!

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For division of line segment AB in ratio 5:2 by point C, the coordinates of point C can be calculated as

Xc = (5*Xb + 2*Xa)/(5+2) = (5*-7 + 2*0)/7 = -35/7 = -5.

Similarly, Yc = (5*Yb + 2*Ya)/(5+2). = (5*-4 + 2*10)/7 = 0.

Thus the point C is (-5,0).

Hope this helps.

Hi your answer is ready ..... but it has got some explanation to do so i had to write it on a paper and upload it for you

**plz check the attachment for detailed solution**.

the answer is **3) (-5,0)**

**Hope this will help you :)**

**Images:**

Any point C(x,y) which divides the line joining A(x1,y1) and B(x2,y2) in the ratio m:n

then c(x,y)=((mx2+nx1)/m+n, (my2+ny1)/m+n)

here in the given question A(0,10) and B(-7,-4)

and m=5 and n=2

substitute in the above formula then you will get C(-5,0)