The equation necessary to solve this problem is:

m`` =dsin``

In this problem m is equal to 1 as we have been given the angle of the first order maximum: ``

The above equation is then simplified to: `` =dsin``

In order to calculate the slit spacing, d, we divide 1 cm by the...

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The equation necessary to solve this problem is:

m`` =dsin``

In this problem m is equal to 1 as we have been given the angle of the first order maximum: ``

The above equation is then simplified to: `` =dsin``

In order to calculate the slit spacing, d, we divide 1 cm by the diffraction gradient: d = 1/5000 = 0.0002 cm.

In order to simplify the conversion of the wavelength units to nanometers (nm), this spacing is converted to a unit of meters: d = 0.0002/100 = 2.0x10^-6 m

Substituting the known parameters into the equation for `` we get:

= (2.0x10^-6)sin(11.8) = 4.09x10^-7 m = 409 nm

Therefore, the correct answer to this question is B) 409 nm.

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