Differentiate y = (sqrt x + x)/x^2

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The derivative of `y = (sqrt x + x)/x^2` has to be determined.

Now for the function `y = (sqrt x + x)/x^2` divide each term of the numerator by the denominator x^2.

This gives:

`y = (x^(1/2) + x)/x^2`

= `x^(-3/2) + x^-1`

The derivative of `y = x^n`...

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The derivative of `y = (sqrt x + x)/x^2` has to be determined.

Now for the function `y = (sqrt x + x)/x^2` divide each term of the numerator by the denominator x^2.

This gives:

`y = (x^(1/2) + x)/x^2`

= `x^(-3/2) + x^-1`

The derivative of `y = x^n` is `y' = n*x^(n-1)`

For `y = x^(-3/2) + x^-1`

`y' = (-3/2)*x^(-5/2) - 1*x^(-2)`

The derivative of `y = (sqrt x + x)/x^2` is `y'= (-3/2)*x^(-5/2) - 1*x^(-2)`

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