Determine whether the point (5,2) lies inside or outside the circle whose equation is x^2+y^2 = 30.

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embizze's profile pic

embizze | High School Teacher | (Level 2) Educator Emeritus

Posted on

The equation of the circle is `x^2+y^2=30` .

Then the inequality for the interior (the disk) is `x^2+y^2<30` and the inequality for the exterior is `x^2+y^2>30` .

Substitute x=5 and y=2 to get 29<30.

The point lies in the interior.

aruv's profile pic

aruv | High School Teacher | (Level 2) Valedictorian

Posted on

Equatio f the given circle is



cetre of circle (0,0)

radius of circle= sqrt(30)

distance d  between (0,0) and point (5,2)




since d is less than radius of the circle So point will inside the circle.


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