Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that a? f(x) = square root (20 − x), [−5, 20]If the Mean Value Theorem can be applied,...
Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that a?
If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that
f '(c) =
f (b) − f (a)
b − a
. (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.)
c =
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You need to use the mean value theorem for the function `f(x) = sqrt(20-x)` , over the interval `[-5,20` ] such that:
`f(20) - f(-5) = f'(c)(20 - (-5))`
You need to remember that `c in (-5,20)` and you need to evaluate `f'(x), ` then you need to substitute c for x in equation representing `f'(x) ` such that:
`f'(x) = (sqrt(20-x))' => f'(x) = ((20-x)')/(2sqrt(20-x))`
`f'(x) = -1/(2sqrt(20-x)) => f'(c) = -1/(2sqrt(20-c))`
You need to evaluate `f(20) ` and `f(-5) ` such that:
`f(20) = sqrt(20-20) = 0`
`f(-5) = sqrt(20+5) = sqrt25 = 5`
Substituting these values in equation representing the mean value theorem yields:
`0 - 5 = -25/(2sqrt(20-c)) => -5 = -25/(2sqrt(20-c))`
Reducing by -`5` yields:
`1 = 5/(2sqrt(20-c)) => 2sqrt(20-c) = 5`
You need to raise to square to remove the square root such that:
`4(20-c) = 25 => 20 - c = 25/4 => c = 20 - 25/4 => c = 55/4 = 13.75in (-5,20).`
Hence, evaluating `c in (-5,20),` for the given function, using mean value theorem yields `c = 13.75` .
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f '(c) =
(f (b) − f (a)) /
(b − a)
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