Determine the vertex of the function 2x^2-7x+5

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f(x) = 2x^2 - 7x + 5

we know that:

a= 2      b = -7     c = 5

We also know that the vertix V is:

v ( vx , vy )    such that:

vx=  -b/2a

vy= - (b^2 - 4ac)/4a

Let us calculate:

vx= -b/2a = 7/2*2 = 7/4

vy...

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f(x) = 2x^2 - 7x + 5

we know that:

a= 2      b = -7     c = 5

We also know that the vertix V is:

v ( vx , vy )    such that:

vx=  -b/2a

vy= - (b^2 - 4ac)/4a

Let us calculate:

vx= -b/2a = 7/2*2 = 7/4

vy = - (b^2 - 4ac)/4a = -(49 - 4*2*5)/4*2

                                    = -9/8

==> vy = -9/8

Then the vertix v is:

V ( 7/4, -9/8)

Approved by eNotes Editorial Team