We have to solve (x+5)^2-4(4x+5)=0
(x+5)^2 - 4(4x+5) = 0
open the brackets
x^2 + 10x + 25 - 16x - 20 = 0
=> x^2 - 6x + 5 = 0
=> x^2 - 5x - x + 5 = 0
=> x( x - 5) - 1(x - 5) = 0
=> (x - )(x - 5) = 0
Therefore x = 1 and x = 5
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