Determine the area of the region bounded by y=4x+3, y=6-x-2x^2, x=-4, and x=2.
To determine the bounded region, graph the given equations. See the attached image for the graph I've created.
Base on the graph, there are three bounded regions.
To get the area of each bounded region, draw a vertical strip on each region. The vertical strips each have a width of dx. And the height of each vertical strip is `y_(upper)-y_(lower)` .
For the bounded region at the left, its height is:
`h=y_(upper) - y_(lower)`
`h = 4x +3 - (6 -x - 2x^2)`
`h = 2x^2+ 5x - 3`
So the expression that represents the area of this vertical strip is:
`A = height * width`
` ` `A = (2x^2+5x- 3)dx`
The bounded region at the left starts from x = -4 and ends at x=-3. So, the integral needed to get the area of this bounded region is:
`A = int_-4^-3 (2x^2+5x - 3)dx `
Evaluating this integral, the result will be:
`A = (2x^3)/3 +...
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