d1: -2x + 3y + 1 = 0

d2: 2x - 3y +1 = 0

For d1:

d1: -2x + 3y +1 = 0

==> y = (2/3)x + 1/2

**Then the slope is m = 2/3** The y-intercept is where the function intersect with y-axis, then x should be...

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d1: -2x + 3y + 1 = 0

d2: 2x - 3y +1 = 0

For d1:

d1: -2x + 3y +1 = 0

==> y = (2/3)x + 1/2

**Then the slope is m = 2/3**

The y-intercept is where the function intersect with y-axis, then x should be 0:

==> y= (2/3)*0 + 1/3 = 1/3

**Then y-intercept = 1/3**

** **

For d2:

d2= 2x+3y +1 = 0

==> y= (-2/3)x -1/3

Then the slope m = -2/3

The y-intercept = -1/3