Determine the slope of the line 8x - 32y -9 = 0?
We have to find the slope of the line 8x – 32y -9 =0.
First we express the equation in the form y = mx+c, where m is the slope of the line and c is the y-intercept.
8x – 32y -9 =0
keep y on one side and move x and the constant to the other side
=> -32y = 9-8x
divide both the sides by -32
=> y = (9/-32) + (8/32) x
simplify all the factors
=> y = -9/32 +x/4
Therefore we get that m = 1/4 for the given equation.
The required slope is 1/4.
The slope of an equation in the form y = mx+c is m.
So the given equation 8x - 32y -9 = 0 can be rewritten by subtracting (8x-9) as:
-32y = -8x+9. Dvide by -32 and we get:
y = (-8/32)x+9/-32)
y = (1/4)x - 9/32
Identify the above equation with y = mx+c, we get m = 1/4.
Therefore the slope of the given equation is slope = 1/4.