A line can be written with the parameters of slope and the y intercept as y=mx+c where m is the slope and c is the y intercept.

Writing 2x-36y-1=0 in the form y=mx+c we get

36y=2x-1 or y=2/36x-1/36 or y=1/18x-1/36.

Therefore m=1/18 or the slope is 1/18

The slope of ax+by+c = 0 is the ratio m given by:

m = -coefficient of x)/(coefficienty) = -a/b.

Here for the equation 2x-36y-1 =0, the slope is m = -2/(-36) = 1/18.

First, we'll put the given equation in the standard form:

y=mx + n, where the coefficients represent:

- m - the slope

- n - y intercept

2x - 36y -1 = 0

We'll isolate -36y to the left side:

-36y=-2x+1

We'll divide by -36 both sides:

y=(-2/-36)x + 1/-36

The standard form of the equation is:

**y = x/18 - 1/36**

**The slope of the line 2x - 36y -1 = 0 is m = 1/18.**