# Determine the point on the x and y axes where 16x + y + 10 =0 intersects them.

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We are given the line 16x + y + 10 =0. Now we need to find the point in the x and y axes where this line intersects them. That is the x and the y intercepts. we can write the line in the form x/a+y/b=1

where a is the x intercept and b is the y intercept.

16x + y + 10 =0

Mover the constant to the other side

16x + y = -10

Divide all the terms by -10

(16/-10) x + y/-10 = 1

=> x/ (-10/16) + y/ (-10) =1

Therefore the x and the y intercepts are (-10/16,0) and (0,-10).

**So the line intersects the x axis at (-10/16, 0) and the y axis at (0, -10)**

The points where 16x+y+10 = 0 intersects x axis is got by putting y=0 in the equation and solving for x.

Therefore 16x+0+10 = 0

16x = -10

x = -10/16

x = -5/8 is the x intercept.

To y intercept , we put x= 0 in the give equation, 16x+y +10 = 0 and solve for y.

16*0+y +10 = 0

y = 10-16 = -6

y = -6 is the y intercept