Determine the point on the x and y axes where 16x + y + 10 =0 intersects them.
We are given the line 16x + y + 10 =0. Now we need to find the point in the x and y axes where this line intersects them. That is the x and the y intercepts. we can write the line in the form x/a+y/b=1
where a is the x intercept and b is the y intercept.
16x + y + 10 =0
Mover the constant to the other side
16x + y = -10
Divide all the terms by -10
(16/-10) x + y/-10 = 1
=> x/ (-10/16) + y/ (-10) =1
Therefore the x and the y intercepts are (-10/16,0) and (0,-10).
So the line intersects the x axis at (-10/16, 0) and the y axis at (0, -10)
The points where 16x+y+10 = 0 intersects x axis is got by putting y=0 in the equation and solving for x.
Therefore 16x+0+10 = 0
16x = -10
x = -10/16
x = -5/8 is the x intercept.
To y intercept , we put x= 0 in the give equation, 16x+y +10 = 0 and solve for y.
16*0+y +10 = 0
y = 10-16 = -6
y = -6 is the y intercept