Determine the general solution to sin(x/3)=(sqrt3)/2. use radian measure in your solution

Expert Answers

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You need to use arcfunctions to solve the equation such that:

`sin (x/3) = sqrt3/2 =gt x/3 = (-1)^n*arcsin (sqrt3/2) + n*pi`

`x/3 = (-1)^n*pi/3 + n*pi`

`x = (-1)^n*3pi/3 + 3n*pi`

`x = (-1)^n*pi + 3n*pi`

Hence, evaluating the general solution to equation `sin (x/3) = sqrt3/2 ` yields `x = (-1)^n*pi + 3n*pi.`

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