Determine the general form of the equation of the line.Determine the general form of the equation of the line that passes through the point (1;0) and (2;1)

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tonys538's profile pic

tonys538 | Student, Undergraduate | (Level 1) Valedictorian

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The equation of a line passing through two points A(x1, y1) and B(x2, y2) is:

`(y - y2)/(x - x2) = (y1 - y2)/(x1 - x2)`

For the points (1, 0) and (2, 1) the equation of the line passing through them is:

`(y - 0)/(x - 1) = (1 - 0)/(2 - 1)`

`y/(x - 1) = 1/1`

y = x - 1

x - y - 1 = 0

The required equation of the line passing through the points (1, 0) and (2, 1) is x - y - 1 = 0

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

The equation of the line that passes through the points is:

(2-1)/(x-1) = (1-0)/(y-0)

We'll compute and we'll get:

1/(x-1) = 1/y

We'll cross multiply and we'll get:

(x-1) = y

We'll write the general form of the equation shifting all terms to the left:

ax + by  +c = 0

x - y - 1 = 0

The equation of the line is: x - y - 1 = 0

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