# Determine the equation of the line that has the slope of .75 and that passes through the point (4, 4.50)

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### 2 Answers

The equation of the line is given by :

y-y1 = m(x-x1) such that (x1,y1) is any point on the line and m is the slope.

We are given that the point (4,4.5) passes through the line, and the slope m= 0.75

==> y- 4-5 = 0.75 (x-4)

==> y- 4.5 = 0.75x - 3

Now add 4.5

==> y= (0.75)x - 3 + 4.5

**==> y= (0.75) x + 1.5**

We want the equation of the line that has the slope of .75 and that passes through the point (4, 4.50)

Given a point and its slope, its best to use the point slope form which in general terms is

y - y1 = m(x - x1) where (x1,y1) is the point and m is the slope.

Plug in to this formula.

y - 4.5 = .75(x - 4)