To solve for the empirical formula, the knowledge of mole ratio is important.
We have two species in the problem, chlorine and oxygen. To get the mole subscripts, we should divide the moles with the lowest number of moles among them. Since only have two species, we use the lower, the moles of chlorine.
`(0.315 mol es C h l o r i n e)/(0.315 mol es ) = 1`
`(1.1 mol es O x y g e n)/(0.315 mol es) = 3.50`
Now we have a ratio of 1 is to 3.5. Generally, we do not put decimals on the subscripts when writing the empirical formula.
So instead of writing `ClO_3.5` , we can multiply it by two to have `Cl_2O_7` .` `` `
The name of the compound is called Dichlorine heptoxide.